[Math] C3: shredded

xp0int Posted on Nov 23 2018

一个切碎的二维码。把不确定的爆破就好了。
```python
import itertools
import os

from PIL import Image
import concurrent.futures
import random
import string
from pyzbar.pyzbar import decode as qrdecode

# 0 9 11 5 6 2 16 25 15 26 3 4 10 20 19 21 7 8 1 22 23 24 18 14 12 13 17

count = 0

chrset = string.ascii_lowercase + string.digits

for v6, v15 in itertools.permutations([6, 15]):
    for v2, v16, v25 in itertools.permutations([2, 16, 25]):
        for v4, v20, v21 in itertools.permutations([4, 20, 21]):
            for v10, v19 in itertools.permutations([10, 19]):
                for v8, v14 in itertools.permutations([8, 14]):
                    for v1, v18 in itertools.permutations([1, 18]):
                        for v22, v23, v24 in itertools.permutations([4, 22, 23, 24], 3):
                            group = [
                                0, 9, 11, 5, v6, v2, v16, v25, v15, 26, 3, v4,
                                v10, v20, v19, v21, 7, v8, v1, v22, v23, v24,
                                v18, v14, 12, 13, 17
                            ]
                            imgnames = [
                                os.path.join('shredded',
                                             str(g) + '.png') for g in group
                            ]
                            imgs = list(map(Image.open, imgnames))
                            widths, heights = zip(*(i.size for i in imgs))

total_width = sum(widths)
                            max_height = max(heights)

new_img = Image.new('RGB', (total_width, max_height))

x_offset = 0
                            for img in imgs:
                                new_img.paste(img, (x_offset, 0))
                                x_offset += img.size[0]

count += 1
                            print(count, end='\r')

decoded = qrdecode(new_img)
                            if decoded:
                                new_img.save('qrcode_%s.png' % ''.join(random.choice(chrset) for _ in range(7)))
                            for d in decoded:
                                print(d.data.decode())

```
![title](https://leanote.com/api/file/getImage?fileId=5bed8796ab64412530007e1d)
![title](https://leanote.com/api/file/getImage?fileId=5bed87d4ab6441233f00846b)
![title](https://leanote.com/api/file/getImage?fileId=5bed87e1ab64412530007e36)

打赏还是打残，这是个问题